10x^2-48x=-32

Solution for 10x^2-48x=-32 equation:

10x^2-48x=-32

We move all terms to the left:

10x^2-48x-(-32)=0

We add all the numbers together, and all the variables

10x^2-48x+32=0

a = 10; b = -48; c = +32;
Δ = b2-4ac
Δ = -482-4·10·32
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-32}{2*10}=\frac{16}{20}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+32}{2*10}=\frac{80}{20}
=4
$